How do you factor #2x^2- 18#?

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Answer 1 · 2015-09-28T21:43:23

The answer is #2(x+3)(x-3)# .

#2x^2-18#

Factor out the GCF #2#.

#2(x^2-9)#

#x^2-9# fits the form #a^2-b^2#, where #a=x and b=3#.

Rewrite the expression.

#2(x^2-3^2)#

#a^2-b^2=(a+b)(a-b)#

#2(x+3)(x-3)#