How do you factor x^4-8x^2-9x48x29?

1 Answer

(x^2+1)(x+3)(x-3)(x2+1)(x+3)(x3)

Explanation:

first lets substitute x^2 = tx2=t
we get t^2 - 8*t - 9t28t9
now split the middle term t^2 + t - 9*t - 9t2+t9t9
factorize now t(t+1) -9(t+1)t(t+1)9(t+1)
now we get (t+1)(t-9)(t+1)(t9)
now substitute back t=x^2t=x2
we get (x^2+1)(x^2-9)(x2+1)(x29)
we can still factorize the x^2-9x29 term
so we get (x^2+1)(x+3)(x-3)(x2+1)(x+3)(x3)
this is the answer