Question

How do you solve `4x^2-4x=0`?

Answer 1

The solutions are
`color(blue)(x=0,x=1`

Explanation:

`4x^2−4x=0`

Both the above terms have `4x` in common:

`4x^2−4x=color(blue)((4x)(x-1)`

Equating the factors to zero we obtain the solutions:

`4x=0, color(blue)(x=0`

`x-1=0, color(blue)(x=1`