How to solve ∫(cos^3x)(sin^2x) dx ?
1 Answer
See the explanation.
Explanation:
= int (1-sin^2x)sin^2x cosx dx
= int (sin^2x-sin^4x)cosx dx
= 1/3sin^3x-1/5sin^5x +C
See the explanation.
= int (1-sin^2x)sin^2x cosx dx
= int (sin^2x-sin^4x)cosx dx
= 1/3sin^3x-1/5sin^5x +C