How do you factor #6y^2 + 11y - 21#?
2 Answers
Sep 29, 2015
Explanation:
using quadratic formula
Sep 30, 2015
Factor f(y) = 6y^2 + 11y - 21
Ans: (6x - 7)(x + 3)
Explanation:
I use the new AC Method to factor trinomials (Socratic Search)
f(y) = 6(y + p)(y + q)
Converted trinomial:
p' and q' have opposite signs. Factor pairs of (-126) --> (-2, 63)(-3, 42)(-6, 21)(-7, 18). This sum is 11 = b. Then p' = -7 ans q' = 18.
Therefor,
Factored form: