Question

How do you find three consecutive odd integers such that twice the sum of the smaller two integers is 25 more than 3 times the largest?

Answer 1

nos are `33, 35, 37`

Explanation:

let the nos be x, x+2, x+4
the equation is
`2*(x+x+2)=3*(x+4)+25`
`4*x+4=3*x+12+25`
`x=33`
nos are `33, 35, 37`