An adult lion standing in Las Vegas has a mass of 210 kg. How much force is exerted downward on the lion by gravity (i.e., the weight)? How much normal force pushes up on the lion?

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Answer 1 · 2015-10-01T20:38:03

F = mg = 210 Kg ( 10 m/s^2) = 2100 Newtons using 10 as an approximation to 9.81 m/s^2.

Answer 2 · 2015-10-01T22:42:30

The weight of the lion is #-2100"N"#, and the normal force is #2100"N"#.

Lion's Weight
#"F"_"W"=mg"#, where #g=-9.81"m/s"^2#

Known:
#m=210"kg"#
#g=-9.8"m/s"^2#

Unknown:
#"F"_"W"# (Weight)

Equation:
#"F"_"W"=mg"#

Solution:
#"F"_"W"=210"kg"xx-9.8"m/s"^2=-2058"N"=-2100"N"# with two significant figures.

Normal force is equal but opposite to the weight of the lion.
#"F"_"N"=-(-2100"N")=2100"N"#