Question

How do you simplify `root4(16) *root4(128)`?

Answer 1

`root(4)(16)*root(4)(128) = 4root(4)(2^(3))`

Explanation:

`2*2*2*2 =16 = 2^4`
`16*2*2*2 = 128 = 2^(4+3) = 2^7`

`root(4)(16)*root(4)(128) = root(4)(2^4)*root(4)(2^(4+3))`
`root(4)(16)*root(4)(128) = 2*2*root(4)(2^(3))`
`root(4)(16)*root(4)(128) = 4root(4)(2^(3))`