How do you factor 6x^3 + 29x^2 + 23x - 30 = 0?

1 Answer
Oct 3, 2015

Technically, you factor 6x^3+29x^2+23x-30 to solve 6x^3+29x^2+23x-30=0

Step 1: find a linear factor
Step 2: factorise and factorise

Explanation:

6x^3+29x^2+23x-30=0

By inspection
6(-3)^3+29(-3)^2+23(-3)-30
=-162+261-69-30=0

Thus (x+3) is a factor

By inspection
(x+3)(6x^2 + 11x - 10)=0
(x+3)(3x - 2)(2x + 5)=0
x=-3 orx=2/3 or x=-5/2