How do you write an equation in slope intercept form for the line parallel to : y=5x-2 that passes through (8, -2)?

1 Answer
Oct 7, 2015

#y=5x+(-42)#

Explanation:

#y=5x-2 (=color(red)(5)x+(color(blue)(-2))#
has a slope of #color(red)(m)=color(red)(5)#

Any line parallel to #y=5x-2# will have the same slope.
That is any line parallel to #y=5x-2# has a slope of #5#

If such a line passes through #(8,-2)# then
#color(white)("XXX")(Deltay)/(Deltax) = (y-(-2))/(x-8) = 5#

#rarrcolor(white)("XXX")y+2=5x-40#

#rarrcolor(white)("XXX")y=5x-42#
which is slope-intercept form with a slope of #5# and a y-intercept of #(-42)#