Question

How do you write an equation in slope intercept form for the line parallel to : y=5x-2 that passes through (8, -2)?

Answer 1

`y=5x+(-42)`

Explanation:

`y=5x-2 (=color(red)(5)x+(color(blue)(-2))`
has a slope of `color(red)(m)=color(red)(5)`

Any line parallel to `y=5x-2` will have the same slope.
That is any line parallel to `y=5x-2` has a slope of `5`

If such a line passes through `(8,-2)` then
`color(white)("XXX")(Deltay)/(Deltax) = (y-(-2))/(x-8) = 5`

`rarrcolor(white)("XXX")y+2=5x-40`

`rarrcolor(white)("XXX")y=5x-42`
which is slope-intercept form with a slope of `5` and a y-intercept of `(-42)`