How do you solve # 6/ (x + 3) = 4/(x - 3)#?

1 Answer
Alan P.
Oct 8, 2015

#x=15#

Explanation:

Given
[1]#color(white)("XXX")6/(x+3)=4/(x-3)#

Multiplying both sides by #(x+3)(x-3)#
[2]#color(white)("XXX")(6cancel(x+3)(x-3))/(cancel(x+3))=(4(x+3)(cancel(x-3)))/cancel(x-3)#

[3]#color(white)("XXX")6(x-3) = 4(x+3)#

Simplifying by distribution
[4]#color(white)("XXX")6x-18 = 4x+12#

Add #(18-4x)# to both sides
[5]#color(white)("XXX")2x = 30#

Divide both sides by #2#
[6]#color(white)("XXX")x=15

Related questions
See all questions in Radical Equations
Impact of this question
1435 views around the world
You can reuse this answer
Creative Commons License