A NASCAR of mass 1400kg has broken down on pit lane. The coefficient of static friction between the tires and the road is 0.55. If the crew pushes with a force of 8046 N, what will the magnitude of the car's acceleration be?

1 Answer
Oct 9, 2015

#0,357m//s^2#

Explanation:

The static frictional force when motion just begins is given by
#f_s=mu_sN#
#=0,55xx1400xx9,8=7546N#

Hence the magnitude of the resultant force will be
#8046-7546=500N#

Therefore by Newton's 2nd Law of motion, the magnitude of the acceleration will be

#a=(sumF)/m=(500N)/(1400kg)=0,357m//s^2#