A 41 kg rock accidentally breaks loose from the edge of a cliff and falls straight down. The magnitude of the air resistance that opposes its downward motion is 260 N. What is the magnitude of the acceleration of the rock?

Question

2481 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-10-09T15:06:30

#3,46m//s^2#

From Newton's 2nd Law of motion,

#sumF=ma#

#therefore mg - f_r=ma#

#therefore a=(mg-f_r)/m=((41xx9,8)-260)/41=3,46m//s^2#