How do you multiply #(3-y^6)(3-y^6)#?

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Answer 1 · 2015-10-10T22:00:55

#9-6y^6 + y^12#

Use the technique FOIL (First Outer Inner Last) to evaluate the multiplication.

First:

#3*3 = 9#

Outer:

#3* - y^6 = -3y^6#

Inner:

#-y^6 * 3 = -3y^6#

Last:

#y^6 *y^6 = y^12#

Now add all the products:

#9 -3y^6 - 3y^6 + y^12 = 9-6y^6 + y^12#

We reach our answer this way.

Hopefully this helped!