Question

Question #f9702

Answer 1

Tom - draw a sketch of the problem and label the lengths of the sides, then use the formula for the volume of a cone.

Explanation:

Here is a sketch of the triangle:

Volume Cone = `1/3pir^2h`

Let's revolve around x which will make `x` the height of the cone. The radius will be `sqrt(10^2-x^2)`

Substitute these values into the formula for Volume:

`Volume =1/3pi[sqrt(10^2-x^2)]^2*x=1/3pi(100x-x^3)`

Since this course does not use calculus yet, graph the function:

`y = 1/3pi(100x-x^3)` between x= 0 and x=10, then use your graphing calculator to find the value for x that will maximize the volume :

`x~~5.7735` `[Volume~~403]`

Hope that helped