Question

How do you differentiate `g(w) = (w^n - 5^n) /n`?

Answer 1

Assuming that `n` is a constant, `g'(w) = w^(n-1)`

Explanation:

Assuming that `n` is a constant,

`g(w) = (w^n - 5^n) /n =1/n(w^n-5^n)`

and `5^n` is constant, so its derivative is `0`.

`g'(w) = 1/n d/(dw)(w^n-5^n)`

`= 1/n (nw^(n-1)-0) = w^(n-1)`