Question

Where should I draw the asymptotes of `(x+2)^2/4-(y+1)^2/16=1`?

Answer 1

Since the positive term includes the variable x, this hyperbola opens up along the x-axis. The equation for the asymptotes is `y=+-b/a(x-h)+k`

Explanation:

`a=sqrt4 = 2`
`b=sqrt16=4`
`h=-2`, `k=-1`

`y=+-b/a(x-h)+k`

`y=+-4/2(x+2)-1`

hope that helped