How do you solve -5 = log_2 x? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer zoe Oct 12, 2015 x=1/32 Explanation: log_2 x=-5 Using the rule log_a M=N rArr M=a^N, you can rewrite log_2x=-5 as x=2^-5 Using the indices rule a^-m=1/a^m, x=1/2^5 x=1/32 Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9^(x-4)=81? How do you solve logx+log(x+15)=2? How do you solve the equation 2 log4(x + 7)-log4(16) = 2? How do you solve 2 log x^4 = 16? How do you solve 2+log_3(2x+5)-log_3x=4? See all questions in Logarithmic Models Impact of this question 1385 views around the world You can reuse this answer Creative Commons License