How do you factor x^3= -3x^2-2x?
1 Answer
Explanation:
iff x * (x^2 + 3x + 2)=0
Now, choose two numbers, whose sum equals the the coefficient of
Here the coefficient of
The coefficient of
and the constant is
So the numbers are 2 & 1
Thus the above expression can be written as
x * (x^2 + 2 x + x + 2)=0
that is
which in turn can be written as
x * (x + 1) * (x + 2) = 0