How do you simplify #12/(x^2-x) * (x^2-1)/(4x-2)#?

1 Answer
Oct 14, 2015

#(6(x+1))/(x(2x-1))#

Explanation:

Your starting expression looks like this

#12/(x^2 - x) * (x^2-1)/(4x - 2)#

The fist fraction can be written as

#12/(x(x-1))#

The second fraction can be written as

#((x-1)(x+1))/(2(2x-1))#

The expression can thus be simplified to

#12/(xcolor(red)(cancel(color(black)((x-1))))) * (color(red)(cancel(color(black)((x-1))))(x+1))/(2(2x-1)) = color(green)((6(x+1))/(x(2x-1)))#