Question

How do you evaluate 2c+ab-3d for a=3,b=5,c=4,d=2?

Answer 1

`17`

Explanation:

If
`color(white)("XXX")color(red)(a=3)`
`color(white)("XXX")color(blue)(b=5)`
`color(white)("XXX")color(green)(c=4)`
`color(white)("XXX")color(cyan)(d=2)`

to evaluate
`color(white)("XXX")2color(green)(c)+color(red)(a)color(blue)(b)-3color(cyan)(d)`

replace each variable letter with its assigned value and apply standard arithmetic.

`color(white)("XXX")2(color(green)(4))+(color(red)(3))(color(blue)(5))-3(color(cyan)(2))`

`color(white)("XXX")=8+15-6`

`color(white)("XXX")=17`