How do you solve #2 e ^ (5x) = 18#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Lovecraft Oct 14, 2015 #x = (2ln(3))/5# Explanation: #2e^(5x) = 18# #e^(5x) = 9# #ln(e^(5x)) = ln(9)# #5x = 2ln(3)# #x = (2ln(3))/5# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 2090 views around the world You can reuse this answer Creative Commons License