In parallel RC circuits, is it true that the larger the value of C, the larger the phase angle?

2 Answers

Yes.

Explanation:

The larger value of C, the smaller is its reactance Xc and the larger is the current Ic.

As the angle is = arctg (Ic/Ir),
the larger Ic the larger the angle.

Jan 25, 2016

Yes.

Explanation:

When an AC voltage having frequency omega is applied across a capacitor of capacity C, the impedance Z_C is given by

Z_C=1/(jomega C), where j-=sqrt -1 also

Capacitive Reactance X_C -=(omegaC)^-1

Now in a parallel RC circuit as shown in the figure
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The total impedance is calculated by adding individual impedance in parallel.

1/Z_(eq)=1/Z_R+1/Z_C=1/R+jomega C=1/R+j/(X_C)
implies Z_(eq)=(RX_C)/(X_C+jR)

The phase angle between the applied voltage and total current is given by
theta=tan^-1 (R/X_C)
We observe that larger value of capacitor will lead to larger phase angle, X_C being in the denominator or C being in the numerator.