How do you evaluate (d+1)(d-1+6) d=2?
1 Answer
Oct 15, 2015
The answer is 21
Explanation:
How to get the answer:
- Replace the variable with the value
#=># #(2+1)(2-1+6)# - First you would do
#(2+1)=3# - The problem is now
#(3)(2-1+6)# - Now you do
#2-1# . You do this instead of doing#1+6# because you do subtraction and addition from left to right - Then you have
#(3)(1+6)# =#(3)(7)# - Parentheses tell you to multiply so the answer you should get is twenty-one
I took a picture of the elongated steps because I describe how to solve inside the parentheses 
