How do you find the integral of 1/tan(x) dx1tan(x)dx?

1 Answer
Oct 17, 2015

ln|sinx| + Cln|sinx|+C

Explanation:

int 1/tanx dx =int 1/(sinx/cosx) dx = int cosx/sinxdx = int (d(sinx))/sinx = ln|sinx| + C1tanxdx=1sinxcosxdx=cosxsinxdx=d(sinx)sinx=ln|sinx|+C