Question

If a net force of 25 N is exerted over a distance of 4 m on a 2 kg mass object and moves it, what is the final velocity?

Answer 1

`10m//s`

Explanation:

From Newton's 2nd Law of Motion,
`sumvec F = m vec a`

Hence the acceleration of the object under this constant resultant force is
`a=(sumF)/m=25/2=12,5m//s^2`

Now assuming the object started from rest, we may use an equation of motion for constant linear acceleration to get the final velocity :

`v^2=u^2+2ax`

`therefore v=sqrt(0^2+2xx12,5xx4)=10m//s`