Question

How do you solve y=4/x and y=3x-1?

Answer 1

For `x_1=-1 => y_1=-4`

For `x_2=4/3 => y_2=3`

Explanation:

`y=4/x` (1)

`y=3*x-1` (2)

Subtracting (1) - (2):

`0 = 4/x-(3x-1)`

`0 = 4/x-3x+1`

`0=4/x-(3x^2+x)/x`

`-3x^2+x+4=0`

Solving the quadratic equation:

`x_1=-1`
`y_1=3xx(-1)-1=-4`

`x_2=4/3`
`y_2=3xx4/3-1 =3`