How do you simplify #(8+x³) / (x+2)#?
1 Answer
Oct 18, 2015
Use the sum of cubes identity:
#(8+x^3)/(x+2) = x^2-2x+4# with exclusion#x != -2#
Explanation:
#8+x^3 = x^3+2^3 = (x+2)(x^2-2x+4)#
So:
#(8+x^3)/(x+2) = ((x+2)(x^2-2x+4))/(x+2) = x^2-2x+4#
with exclusion