How do you find the unknown angle if the adjacent of the triangle is 9 cm , the hypotenuse is 14 cm and the opposite side is unknown?

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Answer 1 · 2015-10-18T23:17:51

#theta=49.99^(o)#

#14xxcos(theta)=9#

#cos(theta)=9/14#

#theta=cos^-1(9/14)=49.99^(o)#

The other side of the triangle is:

#x=sqrt(14^2-9^2)=10.72cm#

The opposite angle is:

#alpha=180-90-49.99=40.01^(o)#
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