Question

How do you convert the cartesian coordinate (3√3, 3) into polar coordinates?

Answer 1

`P=6/_30^(o)`

Explanation:

The module is:

`m^2=(3sqrt(3))^2+3^2`

`m^2=27+9`

`m=sqrt(36)=6`

The angle is:

`phi=tan^-1(3/(3sqrt(3)))`

`phi=30^(o)`

`P=6/_30^(o)`