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How do you simplify $\frac{8}{x^{2} - 4} - \frac{3}{x - 2}$ $8/(x^2-4) – 3/(x-2)$ ?

1 Answer

Oct 19, 2015

$- \frac{1}{x^{2} - 4}$ $-1/(x^2-4)$

Explanation:

So the first thing you will want to do is have common denominators
$\frac{8}{x^{2} - 4} - \frac{9}{x^{2} - 4}$ $8/(x^2-4)-9/(x^2-4)$

then we just finish the equation

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