How do you solve r^2+8r+5=0 using the quadratic formula?

1 Answer
Oct 21, 2015

Explanation:

Think of the coefficient of r^2 as 1, so really it is 1r^2+8r+5, now you just plug in those numbers into the quadratic formula. It would be
1:
(-8+sqrt(8^2-(4)(1)(5)))/(2*1) = -0.68
2:
(-8-sqrt(8^2-(4)(1)(5)))/(2*1) = -7.32

x= -0.68, -7.32