How do you simplify # 7 div(5 - sqrt11)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Alan P. Oct 21, 2015 #7 div (5-sqrt(11)) = (5+sqrt(11))/2# Explanation: #7div(5-sqrt(11)) = 7/(5-sqrt(11))# rationalizing the denominator: #color(white)("XXX")= 7/(5-sqrt(11)) * (5+sqrt(11))/(5+sqrt(11))# #color(white)("XXX")=(7(5+sqrt(11)))/(25-11)# #color(white)("XXX")=(7(5+sqrt(11)))/14# #color(white)("XXX")=(5+sqrt(11))/2# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1299 views around the world You can reuse this answer Creative Commons License