How do solve #ln(x-5) = 3#?

1 Answer
Rafael
Oct 21, 2015

#x=e^3+5#

Explanation:

Simply convert the logarithm to exponential form.

#ln(x-5)=3#

#log_e(x-5)=3#

#hArre^3=x-5#

#color(red)(x=e^3+5)#

I think you can leave it at that. #e# is an irrational number, so you can't really get an exact number. It's around 25.0855369232, in case you're interested. :)

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