Question

How do you solve for x?: `log_6 (36) = 5x + 3`

Answer 1

`x=-1/5`

Explanation:

Using the definition of logs, together with laws of exponents, we may write this equation in exponential form as

`6^(5x+3)=36`

`therefore6^(5x)*6^3=6^2`

`therefore5x+3=2=>-1/5`