How do you solve the following system using substitution?: #x – y = 3, 3x – 2y = 3#

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Answer 1 · 2015-10-24T04:14:04

#color(green)(x = -3#
#color(green)(y = -6#

#x - y = 3#

Transposing #y# to the other side will give us
#x = y + 3# -----------------(i)

Substituting this value of #x# in the second equation given, we get

#3(y+3) - 2y = 3#

#3y + 9 - 2y = 3#

#(3y-2y) + 9 = 3#

#y + 9 = 3#

Transposing 9 to the other side, we get
#y = 3 - 9 #
#color(green)(y = -6#

Substituting this value of #y# in (i), we get
#x = -6 + 3#
#color(green)(x = -3#