How do you expand log (1/ABC) ?

1 Answer
Oct 25, 2015

log(1/ABC)=-log(A)+log(B)+log(C)

Explanation:

[1]" "log(1/ABC)

Property: log_b(mn)=log_b(m)+log_b(n)

[2]" "=log(1/A)+log(B)+log(C)

Property: log_b(m/n)=log_b(m)-log_b(n)

[3]" "=log(1)-log(A)+log(B)+log(C)

Property: log_b(1)=0

[4]" "=color(blue)(-log(A)+log(B)+log(C))