How do you factor #54x^4-2xy^6#? Algebra Polynomials and Factoring Factoring Completely 1 Answer De Rono Oct 27, 2015 #2x(3x-y^2)(9x^2+3xy^2+y^4)# Explanation: #54x^4-2xy^6= 2x(27x^3-y^6)# #=2x((3x)^3-(y^2)^3)= 2x(3x-y^2)(9x^2+3xy^2+y^4)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1518 views around the world You can reuse this answer Creative Commons License