How do you find the explicit formula and calculate term 20 for -1, 6, 25, 62, 123?
1 Answer
Look at sequences of differences to construct a formula and find the
Explanation:
Each of the last 3 terms looks close to a cube, so I could guess the formula as
Write out the initial sequence:
#color(blue)(-1), 6, 25, 62, 123#
Write out the sequence of differences of that sequence:
#color(blue)(7), 19, 37, 61#
Write out the sequence of differences of that sequence:
#color(blue)(12), 18, 24#
Write out the sequence of differences of that sequence:
#color(blue)(6), 6#
Having reached a constant sequence, we can now use the first number of each sequence to write out a formula for
#a_n = color(blue)(-1)/(0!) +color(blue)(7)/(1!) (n-1) + color(blue)(12)/(2!) (n-1)(n-2) + color(blue)(6)/(3!) (n-1)(n-2)(n-3)#
#=-1+7(n-1)+6(n-1)(n-2)+(n-1)(n-2)(n-3)#
#=-1+7n-7+6n^2-18n+12+n^3-6n^2+11n-6#
#=n^3-2#
So