How do you factor #2x^2 + 7x + 3 = 0#?

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Answer 1 · 2015-10-28T23:54:13

#(x+3)(2x+1)#

Our factorization will take the form

#(a+b)(c+d)#

These take practice. In this case I started of as follows

From the FOIL method I know that the last product has to be
#3# so the factors are #1# and #3#

#(a+3)(b+1)#

The middle term of your original expression is #7x#

Therefore

#(x+3)(2x+1)#