What is x if #4x+3/x-9=5#?

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Answer 1 · 2015-10-29T04:16:59

4x + 3/x -9 = 5

multiplying both the sides with x

x ( 4x + 3/x -9) = 5.x

4x.x + 3/x .x -9.x = 5.x

4#x^2# +3 - 9x = 5x

Subtracting 5x from both sides

4#x^2# +3 - 9x -5x = 5x -5x

4#x^2# +3 -14x = 0

4#x^2# -14x + 3 = 0

#4x^2-14x+3# is in the form of a quadratic equation #a^2x+bx+c#, where #a=4, b=-14, and c=3#.

#x=(-b+-sqrt(b^2-4ac))/(2a)=#

#x=(-(-14)+-sqrt((-14^2)-(4*4*3)))/(2*4)#

#x=(14+-sqrt(196-48))/8=#

#x=(14+-sqrt(148))/8#

Solve for #x#.

#x=(14+sqrt148)/8, (14-sqrt 145)/8#