How do you decide whether the relation #(x-3)^2 + (y+1)^2 = 25# defines a function?
1 Answer
Oct 31, 2015
This is a circle of radius
It fails the vertical line test.
For example, the line
Explanation:
For this equation to define
This is expressed in the vertical line test. Any vertical line may only intersect the relation at at most one point in order that the relation be considered a function.
graph{((x-3)^2+(y+1)^2-25)(x-3+y*0.0001) = 0 [-20, 20, -10, 10]}