How do you solve ln(x^2-x+1)-ln(x-1)+ln(x^2-1)=ln9?

1 Answer
Nov 1, 2015

x = 2

Explanation:

ln A + ln B = ln (AB)
ln A - ln B = ln (A/B)

ln (x^2-x+1) - ln (x−1) + ln (x^2−1) = ln 9
ln (((x^2-x+1)(x^2−1))/(x−1)) = ln 9
ln (((x^2-x+1)(x−1)(x+1))/(x−1)) = ln 9
(x^2-x+1)(x+1) = 9
x^3 = 8
x = 2