How do you solve #ln(x^2-x+1)-ln(x-1)+ln(x^2-1)=ln9#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer cspark1981 Nov 1, 2015 # x = 2 # Explanation: # ln A + ln B = ln (AB) # # ln A - ln B = ln (A/B) # # ln (x^2-x+1) - ln (x−1) + ln (x^2−1) = ln 9 # # ln (((x^2-x+1)(x^2−1))/(x−1)) = ln 9 # # ln (((x^2-x+1)(x−1)(x+1))/(x−1)) = ln 9 # # (x^2-x+1)(x+1) = 9 # # x^3 = 8 # # x = 2 # Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 1471 views around the world You can reuse this answer Creative Commons License