What is #int 6x^5 -2x^4 + 3x^3 + x^2 - x-2 dx#?

1 Answer
Bio
Nov 1, 2015

#int(6x^5-2x^4+3x^3+x^2-x-2)dx#
#=x^6-frac{2x^5}{5}+frac{3x^4}{4}+frac{x^3}{3}-frac{x^2}{2}-2x+c,# where #c# is the constant of integration

Explanation:

#int(6x^5-2x^4+3x^3+x^2-x-2)dx#
#=int(6x^5)dx-2intx^4dx+3intx^3dx#
#+intx^2dx-intxdx-2intdx#
#=x^6-frac{2x^5}{5}+frac{3x^4}{4}+frac{x^3}{3}-frac{x^2}{2}-2x+c,# where #c# is the constant of integration

Related questions
See all questions in Definite and indefinite integrals
Impact of this question
1422 views around the world
You can reuse this answer
Creative Commons License