A ball thrown horizontally from a point 24 m above the ground, strikes the ground after traveling horizontally a distance of 18 m. With what speed was it thrown?
2 Answers
Explanation:
First of all we get the time of flight from the vertical component:
The horizontal component of velocity is constant so:
see equation [5] and use your calculator :D
Explanation:
by setting the positive y-axis pointing upward and the positive x-axis pointing to the right,
[1]
with
[2]
with
where
at where the ball strikes,
we then isolate t,
and insert t into (1) at the striking point, assuming that y = 0
[3]
isolating
[4]
[5]
and the value of g depends on what you/your teacher uses ranging from [9,10].