Question #c81c4

1 Answer
Nov 3, 2015

t=248791.2 sec = 69.1 t

Explanation:

rate=-(dA)/(dt)=k[A]^2

Integrated rate Law:
1/([A]_t)=k*t+1/([A]_0)

0,249 M of A is used = 95.77%
0.011 M of A is not used = 4.23%

fraction of A not used: 4.23/100=1/23.64

[A]_t=([A]_0)/23.64

and t=t_(1/23.64)

1/(([A]_0)/23.64)=k*t_(1/23.64)+1/[A]_0

t_(1/23.64)=1/k(23.64/[A]_0-1/[A]_0)=1/(3.5*10^(-4))(22.64/0.260)

t_(1/23.64)=248791.2 sec = 69.1 t