Question

The volume of a sample of a gas at 273°C is 200.0 L. If the volume is decreased to 100.0 L at constant pressure, what will be the new temperature of the gas?

Answer 1

`T_2="273 K"`

Explanation:

Charles' Law states that when pressure is held constant, the temperature and volume of a gas are directly proportional, so that if one goes up, so does the other. Note: The temperature needs to be in Kelvins.

The equation for Charles' Law is `V_1/T_1=V_2/T_2`

`V_1="200.0 L"`
`T_1="273"^"o""C+273=546 K"`
`V_2="100.0 L"`
`T_2="?"`

Solution
Rearrange the equation to isolate `T_2` and solve.

`T_2=(V_2T_1)/V_1`

`T_2=(100.0cancel"L"xx546"K")/(200cancel"L")=`

`T_2="273 K"`