Question

How do you solve x = 4y + 8 and 2x - 8y = -3?

Answer 1

This system has no solutions.

Explanation:

This system has no solutions. Multiplying by `2` the first equation, we have

`2x=8y+16`, which we can rewrite as `2x-8y=16`. So, the system becomes

`{ (2x-8y=+16),(2x-8y=-3):}`

And you can see this is impossible: if the same quantity (namely `2x-8y`) is equal to both `16` and `-3`, then also `16=-3`, which is clearly false.