How do you find the intercepts for #y=-2x+5#?

1 Answer
Nov 7, 2015

x-axis: (2.5 , 0)
y-axis: (0 , 5)

Explanation:

Since this is a linear function with a form #y = ax + b#, it is only intercepting the x-axis and y-axis once.

How to solve interception with x-axis:
Here you know that y = 0, and this gives you
# y = -2x + 5#
# 0 = -2x + 5#
# 2x = 5 #
Divide both by two
# x = 2.5#

How to solve interception with y-axis:
Here you know that x = 0, and this gives you:
#y = -2x + 5#
#y = -2 * 0 + 5#
#y = 5#

Therefore, you get interception points at (2.5 , 0) and (0 , 5).