How do you solve #(3x - 5) ( x - 2 ) < 0 #?

1 Answer
Alan P.
Nov 7, 2015

#x in (5/3,2)#

Explanation:

#(3x-5)(x-2)# is the equation of a parabola
with x-intercepts at #5/3# and #2#

If expanded into standard form the leading term is #3x^2#

#rArr# the leading term coefficient is positive

#rArr# the parabola opens upward

#rArr# the points between the x-intercepts are below the X-axis

#rArr# the value of the parabola is #< 0# when #x in (5/3, 2)#

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